Internal mixer has a fixed volume mixing chamber and therefore only one particular total amount of ingredients is the correct one.
Thus we need to calculate the correct batch weight, based on the density or the specific gravity of the ingredients and volume of the mixing chamber. This step involves the multiplication of formulation quantity in phr by a fill factor, which is a ratio of optimum mix volume to formulation volume.
CALCULATING OPTIMUM BATCH WEIGHT
Internal mixer chamber volume = 50 L
Optimum mix volume (80%) = 40 L
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Compounding |
Parts |
Density |
Volume |
Batch weight |
ingredients |
(phr) |
kg/L |
(L) |
(kg) |
SMR 10 |
100 |
0.94 |
106.4 |
25.810 |
Zinc oxide |
10 |
5.55 |
1.8 |
2.581 |
Stearic acid |
2 |
0.92 |
2.2 |
0.516 |
N550 Carbon Black |
50 |
1.80 |
27.8 |
12.910 |
Oil (naphtenic) |
10 |
0.92 |
10.9 |
2.581 |
Antioxidant TMQ |
2 |
1.08 |
1.9 |
0.516 |
Antiozonant DPPD |
2 |
1.22 |
1.6 |
0.516 |
Sulphur |
0.25 |
2.07 |
0.1 |
0.065 |
TBBS |
2.10 |
1.29 |
1.6 |
0.542 |
TMTD |
1 |
1.35 |
0.7 |
0.258 |
Total |
179.35 |
1.16 |
155.0 |
46.290 |
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Total formulation phr = 179.35 phr
Total formulation volume = 155 L
Formulation density (ρ = m/V) = 179.35 kg/155 L = 1.16 kg/L
Fill factor = (optimum volume)/(formulation volume) = 40 L/155 L
∴ fill factor = 0.258
Each Ingredient phr x fill factor = weight of each ingredient in a batch
Eg: Rubber → 100 x 0.258 = 25.80 kg
Carbon Black → 50 x 0.258 = 12.91 kg
TBBS → 2.1 x 0.258 = 0.54 kg
Total wt of ingredients = Batch weight = 46.29 kg
Batch volume = Batch weight/density = 46.29/1.16 = 40 L
This confirms that the calculated batch weight of 46.29 kg will occupy exactly 40 L volume which is 80% of chamber full capacity (50 L).